F(x)=Ln(x^1/2)

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Solution for F(x)=Ln(x^1/2) equation: 


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(1.005)^(36)

35;4

(5*x-x^2-6)/(x^3-(4*x)) = 0

((-x)^2+5*x-6)/(x^3-(4*x)) = 0

-((6/3)*x)-2/9 = 0

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